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Eureka Math Grade 5 Module 2 Lesson 3 Answer Key
Engage ny eureka math 5th grade module 2 lesson 3 answer key, eureka math grade 5 module 2 lesson 3 problem set answer key.
Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 8 and 7, doubled
Answer: The sum of 8 and 7, doubled = 30.
b. 4 times the sum of 14 and 26
Answer: The sum of 14 and 26, 4 times = 160.
c. 3 times the difference between 37.5 and 24.5
Answer: The difference of 37.5 and 24.5, 3 times = 13.0.
d. The sum of 3 sixteens and 2 nines
Answer: The sum of 3 sixteens and 2 nines = 30.
e. The difference between 4 twenty-fives and 3 twenty-fives
Answer: The difference between 4 25 and 3 25 = 25.
f. Triple the sum of 33 and 27
Answer: The sum of 33 and 27, 3 times = 180.
Question 2. Write the numerical expressions in words. Then, solve.
| Expression | Words | The Value of the Expression |
| a. 12 × (5 + 25) | 12 times the sum of 5 and 25 | 12 x ( 30) = 360 |
| b. (62 – 12) × 11 | 11 times the difference of 62 and 12 | (50) x 11 = 550 |
| c. (45 + 55) × 23 | 23 times the sum of 45 and 55 | (100) x 23 = 2300 |
| d. (30 × 2) + (8 × 2) | product of 30,2 and product of 8,2 | (60) + (16) = 76 |
Answer: 360.
Explanation: In the above-given question, given that, 12 x ( 5 + 25). 12 x (30). 360.
Answer: 550.
Explanation: In the above-given question, given that, (62 – 12) × 11 50 x 11 = 550.
Answer: 2300.
Explanation: In the above-given question, given that, (45 + 55) × 23. 100 x 23. 2300.
Answer: 76.
Explanation: In the above-given question, given that, (30 × 2) + (8 × 2) 60 + 16. 76.
Answer: 600 > 360.
Explanation: In the above-given question, given that, 24 x (20 + 5). 24 x 25. 600. (20 + 5) x 12. 30 x 12. 360. 600 > 360.
Answer: 487 > 513.
Explanation: In the above-given question, given that, 18 x 27. 487. 20 twenty-seven – 1 27. 540 – 27. 513. 487 < 513.
Answer: 171 = 171.
Question 4. Mr. Huynh wrote the sum of 7 fifteens and 38 fifteens on the board. Draw a model, and write the correct expression.
Answer: The sum of 7 fifteens and 38 fifteens = 675.
Question 5. Two students wrote the following numerical expressions. Angeline: (7 + 15) × (38 + 15) MeiLing: 15 × (7 + 38) Are the students’ expressions equivalent to your answer in Problem 4? Explain your answer.
Answer: Yes, the student’s expressions equivalent.
Explanation: In the above-given question, given that, Angeline: (7 + 15) × (38 + 15) Meiling: 15 × (7 + 38) 105 + 570 = 675.
Question 6. A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. a. Write an expression to show how to find the total number of oranges ordered.
Answer: The total number of oranges ordered= 480.
Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480
b. Next week, Mr. Lee will double the number of boxes he orders. Write a new expression to represent the number of oranges in next week’s order.
Answer: The total number of oranges ordered= 960.
Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480 + 480 = 960
c. Evaluate your expression from Part (b) to find the total number of oranges ordered in both weeks.
Answer: The total number of oranges ordered in both weeks = 1440.
Explanation: In the above-given question, given that, 960 + 480 = 1440.
Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key
Question 1. Draw a model. Then, write the numerical expressions. a. The difference between 8 forty-sevens and 7 forty-sevens
Answer: The difference of 8 forty-sevens and 7 forty-sevens = 47.
Explanation: In the above-given question, given that, the difference of 8 forty sevens and 7 forty-sevens. 8 x 47 – 7 x 47. 376 – 329. 47
b. 6 times the sum of 12 and 8
Answer: The sum of 12 and 8, 6 times = 120.
Explanation: In the above-given question, given that, the sum of 12 and 8 is 120. 20 + 20 + 20 + 20 + 20 + 20 = 120. 12 + 8 = 20.
Answer: 4836 > 2028.
Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key
Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 21 and 4, doubled b. 5 times the sum of 7 and 23 c. 2 times the difference between 49.5 and 37.5 d. The sum of 3 fifteens and 4 twos e. The difference between 9 thirty-sevens and 8 thirty-sevens f. Triple the sum of 45 and 55
Answer: The sum of 21 and 4, 2 times = 50.
Answer: The sum of 7 and 23, 5 times = 150.
Answer: 2 times the difference between 49.5 and 37.5 = 24.
Answer: The sum of 3 fifteens and 4 twos = 53.
Answer: The difference between 9 thirty-sevens and 8 thirty-sevens = 37.
Explanation: In the above-given question, given that, The difference between 9 thirty-sevens and 8 thirty-sevens 9 x 37 – 8 x 37. 333 – 296. 37.
Triple the sum of 45 and 55 = 300.
Explanation: In the above-given question, given that, Triple the sum of 45 and 55 45 + 55 = 100. 100 + 100 + 100 = 300.
| Expression | Words | The Value of the Expression |
| a. 10 × (2.5 + 13.5) | one hundred and sixty | 10 x (16) = 160 |
| b. (98 – 78) × 11 | two hundred and twenty | (20) x 11 = 220 |
| c. (71 + 29) × 26 | two thousand six hundred | (100) x 26 = 2600 |
| d. (50 × 2) + (15 × 2) | one hundred and thirty | (100) + 30 = 130 |
Answer: 160.
Explanation: In the above-given question, given that, 10 x ( 2.5 + 13.5). 10 x (16). 160.
Answer: 220.
Explanation: In the above-given question, given that, 11 x ( 98 – 78). 11 x (20). 220.
Answer: 2600.
Explanation: In the above-given question, given that, 26 x ( 71 + 29). 26 x (30). 2600.
Answer: 3000.
Explanation: In the above-given question, given that, (50 x 2) + ( 15 + 2). 100 x (30). 3000.
Answer: 3906 > 1438.
Explanation: In the above-given question, given that, 93 x ( 40 + 2). 93 x (42). 3906. (40 + 2) x 36 42 x 36. 1438. 3906 > 1438.
Answer: 1525 > 1475.
Explanation: In the above-given question, given that, 61 x ( 25). 1525. 60 twenty fives minus one twenty-five. 60 x 25 – 25. 1500 – 25. 1475. 1525 > 1475.
Question 4. Larry claims that (14 + 12) × (8 + 12) and (14 × 12) + (8 × 12) are equivalent because they have the same digits and the same operations. a. Is Larry correct? Explain your thinking.
Answer: Yes, Larry was not correct.
Explanation: In the above-given question, given that, Larry claims that (14 + 12) x (8 + 12) and (14 x 12) + (8 x 12). 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.
b. Which expression is greater? How much greater?
Answer: (14 + 12) x (8 + 12) is greater. 256 is greater.
Explanation: In the above-given question, given that, 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.
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Chapter 5: Ratios and Proportions
Chapter 5 homework solutions.
5.1-5.3 Extra Practice Worksheet
5.1 Ratios and Rates
5.1 Lesson Preso
5.1 Textbook Exercises: page 167
Ba: 1-6, 11-27 odd;
Avg: 1-6, 11-21 odd, 24-28 even, 29, 31;
Adv: 1-6, 18-38 even
5.2 Proportions
5.2 Textbook Exercises page 174
Ba: 1-4, 5-13 odd, 21-27 odd;
Avg 1-4, 5-13 odd, 22-30 even;
Adv: 1-4, 6-14 even, 22-32 even
5.3 Writing Proportions
5.3 Lesson Preso
5.3 Textbook Exercises page 182
Ba: 1-3, 9, 11, 12, 13-23 odd
Avg: 1-3, 8-14 even, 19-23
Adv: 1-3, 8-24 even, 25
5.4 Solving Proportions
5.4 Lesson Preso
5.4 Textbook Exercises page 190
Ba: 1-3, 5-9 odd, 15-21 odd, 22, 23-27 odd
Avg: 1-3, 5-9 odd, 15-21 odd, 22, 29, 30, 32-35
Adv: 1-3, 4-8 even, 14-38 even
5.5 Lesson Preso
5.5 Textbook Exercises page 196
Ba: 1-3, 5-11 odd, 12, 13-17 odd
Avg: 1-3, 5-11 odd, 12, 14-17
Adv: 1-3, 4-18 even
5.6 Direct Variation
5.6 Lesson Preso
5.6 Textbook Exercises page 202
Ba: 1-3, 7-17 odd, 18, 19-25 odd
Avg: 1-3, 7-17 odd, 18-28 even
Adv: 1-3, 8-28 even
Chapter 5 Review
5.1-5.3 Review Quizizz:
5.4-5.6 Review Quizizz:
Chapter 5 Review Quizizz:
Home > CC3 > Chapter 2 > Lesson 2.1.5
Lesson 2.1.1, lesson 2.1.2, lesson 2.1.3, lesson 2.1.4, lesson 2.1.5, lesson 2.1.6, lesson 2.1.7, lesson 2.1.8, lesson 2.1.9.
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The source for the homework pages is the "full module" PDF, available here for free:https://www.engageny.org/resource/grade-2-mathematics-module-5
Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key. Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 21 and 4, doubled. b. 5 times the sum of 7 and 23. c. 2 times the difference between 49.5 and 37.5. d.
EngageNY Grade 5 Module 2 Lesson 3For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical difficulty (audio s...
Lesson 3 Homework . 2 5 . 2 5 . 2. Solve using the arrow way or mental math. Use scrap paper if needed. a. 320 + 200 = 280 + 320 = 290 + 320 = b. 130 + 500 = 130 + 560 = 130 + 580 = c. 360 + 240 = 350 + 270 = 380 + 230 = d. 260 + 250 = 270 + 280 = 280 + 250 = e. 440 + 280 = 660 + 160 = _ 770 + 150 = 3. Solve.
EngageNY/Eureka Math Grade 2 Module 5 Lesson 3For more videos, please visit http://bit.ly/engageportalPLEASE leave a message if a video has a technical diffi...
CPM Education Program proudly works to offer more and better math education to more students.
CPM Education Program proudly works to offer more and better math education to more students.
CPM Education Program proudly works to offer more and better math education to more students.
3. 4.9 ! 7 " __ 4. 3.6 ! 9 " __ 5. 2.4 ! 8 " __ Use the model to complete the number sentence. Divide. Use base-ten blocks. ... Include pictures to support your explanation. Lesson 5.2 Practice and Homework COMMON CORE STANDARD—5.NBT.B.7 Perform operations with multi-digit whole numbers and with decimals to hundredths. Personal Math Trainer ...
Go Math! Practice Book (TE), G5. Name Divide Decimals bg Whole Numbers use the model to complete the number sentence. 1. 1.2 Divide. use base-ten blocks. 2. Lesson 5.2 COMMON CORE STANDARD CC.5.NBT.7 Perform operations with multi-digit whole numbers and with decimals to hundredths. 1. 3.69 - 3 = lìììììììììì 23.
Verified answer. How many positive integers between 100 and 999 inclusive are divisible by three or four? star. 4.1 /5. heart. 16. Lesson 3 homework 5.2 Get the answers you need, now!
The notation P (F|E) means the probability of event F given event E. True. Study with Quizlet and memorize flashcards containing terms like In a probability model, the sum of the probabilities of all outcomes must equal 1. True or False?, Probability of a measure of the likelihood of a random phenomenon or chance behavior.
Engage NY // Eureka Math Grade 5 Module 5 Lesson 3 Homework
Lesson 5.2 - The Addition Rule. Relevant Context. Do people lie in their online dating profiles? Stats Content (CED Topics 4.4 & 4.6) Unions & Intersections. The Addition Rule. Two-Way Tables, Venn Diagrams. All lesson materials are included below. Before using them: Make a free account for access.
Lesson 5.2 (Solving Systems of Linear Equations by Substitution) Flashcards; Learn; Test; Match; Q-Chat; Get a hint. solve by substitution: y = 4x and x + y = 5 (1, 4) 1 / 12. 1 / 12. Flashcards; Learn; Test; Match; Q-Chat; Created by. oconnormath Teacher. Share. Find the solution to the system by using substitution.
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Extra Ch. 6 Lessons Homework: Lesson #1 Worksheet Answers Lesson #2 Worksheet Answers Extra Ch. 6 Lessons Review: Worksheet Answers--- Chapter 7 Lessons ---7.4 Day 1: Function Operations & Composition 7.1 Higher Roots & Rational Exponents ... 7.3 Homework: Pg 459: 3, 7, 8 Pg 462: 1, 2
Chapter 5 Review. 5.1-5.3 Review Quizizz: 5.4-5.6 Review Quizizz: Chapter 5 Review Quizizz: Page updated.
3. 42 4. 66 12. Bryson buys a bag of 64 plastic miniature ... Practice and Homework Lesson 5.2. Personal Math Trainer FOR MORE PRACTICE ... have 9 as a factor. 2. What digit(s) can be in the ones place of a number that has 5 as a factor? Lesson Check (4.OA.B.4) 290 3. Write an expression that can be used to find 4 × 275 using mental math and ...
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Lesson 5.1: Configuring the schedule In this lesson, you will learn how to set up a schedule configuration, which controls where the execution results are stored. Lesson 5.2: Running the schedule and viewing the reports In this lesson, you will learn how to run the schedule. Lesson 5.3: Adding virtual users during a run
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